5y^2+20y+25=5

Solution for 5y^2+20y+25=5 equation:

Simplifying
5y2 + 20y + 25 = 5

Reorder the terms:
25 + 20y + 5y2 = 5

Solving
25 + 20y + 5y2 = 5

Solving for variable 'y'.

Reorder the terms:
25 + -5 + 20y + 5y2 = 5 + -5

Combine like terms: 25 + -5 = 20
20 + 20y + 5y2 = 5 + -5

Combine like terms: 5 + -5 = 0
20 + 20y + 5y2 = 0

Factor out the Greatest Common Factor (GCF), '5'.
5(4 + 4y + y2) = 0

Factor a trinomial.
5((2 + y)(2 + y)) = 0

Ignore the factor 5.
Subproblem 1
Set the factor '(2 + y)' equal to zero and attempt to solve:

Simplifying
2 + y = 0

Solving
2 + y = 0

Move all terms containing y to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + y = 0 + -2

Combine like terms: 2 + -2 = 0
0 + y = 0 + -2
y = 0 + -2

Combine like terms: 0 + -2 = -2
y = -2

Simplifying
y = -2
Subproblem 2
Set the factor '(2 + y)' equal to zero and attempt to solve:

Simplifying
2 + y = 0

Solving
2 + y = 0

Move all terms containing y to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + y = 0 + -2

Combine like terms: 2 + -2 = 0
0 + y = 0 + -2
y = 0 + -2

Combine like terms: 0 + -2 = -2
y = -2

Simplifying
y = -2
Solution
y = {-2, -2}